题目
Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties:
Integers in each row are sorted in ascending from left to right.
Integers in each column are sorted in ascending from top to bottom.
For example,
Consider the following matrix:
[
[1, 4, 7, 11, 15],
[2, 5, 8, 12, 19],
[3, 6, 9, 16, 22],
[10, 13, 14, 17, 24],
[18, 21, 23, 26, 30]
]
Given target = 5, return true.
Given target = 20, return false.
思路
杨氏矩阵
代码
#include <iostream>
#include <vector>
#include <stack>
using namespace std;
class Solution {
public:
bool searchMatrix(vector<vector<int>>& matrix, int target) {
if(matrix.empty()){
return false;
}
int row = matrix.size();
int col = matrix[0].size();
int x = 0,y = col - 1;
while(x < row && y >= 0){
if(matrix[x][y] == target){
return true;
}
else if(matrix[x][y] < target){
++x;
}
else{
--y;
}
}
return false;
}
};
int main(){
Solution s;
int target = 20;
vector<vector<int> > matrix = {
{1,4,7,11,15},
{2,5,8,12,19},
{3,6,9,16,22},
{10,13,14,17,24},
{18,21,23,26,30}
};
bool result = s.searchMatrix(matrix,target);
cout<<result<<endl;
return 0;
}
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